Number of compounds from the following which | vedclass

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(A) Benedict's solution is used to detect reducing sugars. Reducing sugars contain a free aldehyde or ketone group that can reduce $Cu^{2+}$ ions to $

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) Benedict's solution is used to detect reducing sugars. Reducing sugars contain a free aldehyde or ketone group that can reduce $Cu^{2+}$ ions to $Cu^+$ ions,forming a red/orange precipitate of $Cu_2O$.Among the given compounds:$1$. Glucose: Reducing sugar (gives test).$2$. Maltose: Reducing sugar (gives test).$3$. Sucrose: Non-reducing sugar (does not give test).$4$. Ribose: Reducing sugar (gives test).$5$. $2$-deoxyribose: Reducing sugar (gives test).$6$. Amylose: Non-reducing polysaccharide (does not give test).$7$. Lactose: Reducing sugar (gives test).Therefore,only $2$ compounds (Sucrose and Amylose) will not produce an orange-red precipitate with Benedict's solution.

Number of compounds from the following which will not produce orange red precipitate with Benedict's solution is $..............$. Glucose,maltose,sucrose,ribose,$2$-deoxyribose,amylose,lactose.

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