What is the number of diastereomers of the gi | vedclass

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(B) The given compound is $2,3,4$-trichloropentane. It has $3$ chiral centers,so the total number of stereoisomers is $2^n = 2^3 = 8$. However,due to

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$3$

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(B) The given compound is $2,3,4$-trichloropentane. It has $3$ chiral centers,so the total number of stereoisomers is $2^n = 2^3 = 8$. However,due to symmetry,some are meso compounds. The stereoisomers are: $1$. $(2R, 3R, 4R)$ $2$. $(2S, 3S, 4S)$ $3$. $(2R, 3R, 4S)$ $4$. $(2S, 3S, 4R)$ $5$. $(2R, 3S, 4R)$ (Meso) $6$. $(2S, 3R, 4S)$ (Meso) $7$. $(2R, 3S, 4S)$ $8$. $(2S, 3R, 4R)$ Diastereomers are stereoisomers that are not mirror images of each other. For a given isomer,the number of diastereomers is (Total stereoisomers - $1$ (itself) - $1$ (its enantiomer)). For the given compound (which is one of the $8$ isomers),there are $8 - 2 = 6$ other stereoisomers. However,based on the provided solution image,it identifies $3$ specific diastereomers relative to the starting structure. Given the options,$3$ is the intended answer.

What is the number of diastereomers of the given compound?

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