Easy
Number of electrons in the outermost orbit of the element of atomic number $15$ is
- A$1$
- B$3$
- C$5$
- D$7$
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Similar Questions
What is the number of unpaired electrons present in the ground state of Silicon $(Si)$ and Chromium $(Cr)$, respectively?
The number of angular and radial nodes of $4d$ orbital respectively are
Match List-$I$ with List-$II$.
List-$I$ (Element) List-$II$ (Electronic Configuration) $A. N$ $I. [Ar] 3d^{10} 4s^2 4p^5$ $B. S$ $II. [Ne] 3s^2 3p^4$ $C. Br$ $III. [He] 2s^2 2p^3$ $D. Kr$ $IV. [Ar] 3d^{10} 4s^2 4p^6$
Choose the correct answer from the options given below:
| List-$I$ (Element) | List-$II$ (Electronic Configuration) |
|---|---|
| $A. N$ | $I. [Ar] 3d^{10} 4s^2 4p^5$ |
| $B. S$ | $II. [Ne] 3s^2 3p^4$ |
| $C. Br$ | $III. [He] 2s^2 2p^3$ |
| $D. Kr$ | $IV. [Ar] 3d^{10} 4s^2 4p^6$ |
Choose the correct answer from the options given below:
Which one represents an impossible arrangement of quantum numbers $(n, l, m, s)$?
Easy
View SolutionFrom the given sets of quantum numbers,the one that is inconsistent with the theory is:
MediumIIT 1994
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