(D) The electronic configuration of Vanadium $(Z=23)$ is: $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{3} 4s^{2}$.The p-orbitals present are $2p$ and $3p$.

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(D) The electronic configuration of Vanadium $(Z=23)$ is: $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{3} 4s^{2}$.The p-orbitals present are $2p$ and $3p$.Number of electrons in $2p$ orbital = $6$.Number of electrons in $3p$ orbital = $6$.Total number of electrons in p-orbitals = $6 + 6 = 12$.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

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Number of electrons that Vanadium $(Z=23)$ has in p-orbitals is equal to $......$

JEE MAIN 2021 All JEE MAIN

A
$24$
B
$66$
C
$89$
D
$12$

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Structure of Atom

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Quantum number, Electronic configuration and Shape of orbitals

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Number of electrons that Vanadium $(Z=23)$ has in p-orbitals is equal to $......$

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