(B) The balanced chemical equation for the reaction of $KMnO_{4}$ with $I^{-}$ in a basic medium is:$2 KMnO_{4} + H_{2}O + KI \rightarrow 2 MnO_{2} +

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(B) The balanced chemical equation for the reaction of $KMnO_{4}$ with $I^{-}$ in a basic medium is:$2 KMnO_{4} + H_{2}O + KI \rightarrow 2 MnO_{2} + 2 KOH + KIO_{3}$From the stoichiometry of the balanced equation,$2 \ mol$ of $KMnO_{4}$ reacts with $1 \ mol$ of $KI$ (which provides $1 \ mol$ of $I^{-}$).Therefore,the number of moles of $KMnO_{4}$ reduced by $1 \ mol$ of $I^{-}$ is $2$.

Class 11 Chemistry Redox Reactions Redox reaction and Method for balancing Redox reaction

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Number of moles of $KMnO_{4}$ reduced by $1 \ mol$ of $I^{-}$ in basic medium is

A
$3$
B
$2$
C
$2/3$
D
$3/2$

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Redox Reactions

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Redox reaction and Method for balancing Redox reaction

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Number of moles of $KMnO_{4}$ reduced by $1 \ mol$ of $I^{-}$ in basic medium is

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