The number of neutrons in a parent nucleus X, | vedclass

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(A) $\beta$ emission increases the atomic number by $1$ while the mass number remains unchanged.Let the parent nucleus be $_Z X^A$.After two successiv

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$9$

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(A) $\beta$ emission increases the atomic number by $1$ while the mass number remains unchanged.Let the parent nucleus be $_Z X^A$.After two successive $\beta$ emissions,the reaction is: $_Z X^A \xrightarrow{-2\beta} _{Z+2} N^{14}$.Comparing the atomic number and mass number,we get $Z+2 = 7$,so $Z = 5$,and $A = 14$.The parent nucleus is $_5 X^{14}$.The number of neutrons in $_5 X^{14}$ is $A - Z = 14 - 5 = 9$.

The number of neutrons in a parent nucleus $X$,which gives a $_7N^{14}$ nucleus after two successive $\beta$ emissions,is:

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