Number of paramagnetic ions among the followi | vedclass

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Question

(A) An ion is paramagnetic if it has one or more unpaired electrons.$1$. $Mn^{2+}$ $([Ar] 3d^5)$: $5$ unpaired electrons (Paramagnetic).$2$. $Cu^{2+}$

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) An ion is paramagnetic if it has one or more unpaired electrons.$1$. $Mn^{2+}$ $([Ar] 3d^5)$: $5$ unpaired electrons (Paramagnetic).$2$. $Cu^{2+}$ $([Ar] 3d^9)$: $1$ unpaired electron (Paramagnetic).$3$. $Zn^{2+}$ $([Ar] 3d^{10})$: $0$ unpaired electrons (Diamagnetic).$4$. $Yb^{2+}$ $([Xe] 4f^{14})$: $0$ unpaired electrons (Diamagnetic).$5$. $Sc^{3+}$ $([Ar] 3d^0)$: $0$ unpaired electrons (Diamagnetic).$6$. $La^{3+}$ $([Xe] 4f^0)$: $0$ unpaired electrons (Diamagnetic).$7$. $Gd^{3+}$ $([Xe] 4f^7)$: $7$ unpaired electrons (Paramagnetic).$8$. $Lu^{3+}$ $([Xe] 4f^{14})$: $0$ unpaired electrons (Diamagnetic).$9$. $Ti^{4+}$ $([Ar] 3d^0)$: $0$ unpaired electrons (Diamagnetic).$10$. $Ce^{4+}$ $([Xe] 4f^0)$: $0$ unpaired electrons (Diamagnetic).The paramagnetic ions are $Mn^{2+}$, $Cu^{2+}$, and $Gd^{3+}$.Total number of paramagnetic ions = $3$.

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