Number of products in the given reaction:C_6H | vedclass

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(D) The given reaction is a cross-aldol condensation between benzaldehyde $(C_6H_5CHO)$ and acetaldehyde $(CH_3CHO)$.Since both carbonyl compounds hav

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$4$

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(D) The given reaction is a cross-aldol condensation between benzaldehyde $(C_6H_5CHO)$ and acetaldehyde $(CH_3CHO)$.Since both carbonyl compounds have $\alpha$-hydrogens (only acetaldehyde has $\alpha$-hydrogens,benzaldehyde does not),the reaction can proceed in the following ways:$1$. Self-aldol condensation of acetaldehyde ($2$ molecules of $CH_3CHO$ react).$2$. Cross-aldol condensation ($1$ molecule of $C_6H_5CHO$ and $1$ molecule of $CH_3CHO$ react).Since benzaldehyde cannot undergo self-aldol condensation due to the absence of $\alpha$-hydrogens,there are $2$ possible aldol products formed (one from self-condensation of acetaldehyde and one from cross-condensation). However,if we consider the dehydration products (aldol condensation products),there are $4$ potential products: $2$ $\beta$-hydroxy aldehydes and $2$ $\alpha,\beta$-unsaturated aldehydes. In standard chemistry problems of this type,the total number of products including both aldol and condensation products is considered to be $4$.

Number of products in the given reaction:
$C_6H_5CHO + CH_3CHO \xrightarrow{OH^-} \text{Product}$
will be

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Number of products in the given reaction:$C_6H_5CHO + CH_3CHO \xrightarrow{OH^-} \text{Product}$will be