(C) The atomic number of Beryllium $(Be)$ is $4$. Its electronic configuration in the ground state is $1s^2, 2s^2$. Since both the $1s$ and $2s$ orbit

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(C) The atomic number of Beryllium $(Be)$ is $4$. Its electronic configuration in the ground state is $1s^2, 2s^2$. Since both the $1s$ and $2s$ orbitals are completely filled with paired electrons,there are no unpaired electrons in the ground state of the Beryllium atom. Therefore,the number of unpaired electrons is $0$.