Observe the following molecules: C_2, N_2, O_ | vedclass

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Question

(B) The correct statement is $(b)$.All these molecules $(C_2, N_2, O_2, F_2)$ are formed by the combination of atomic orbitals of the second period el

Vedclass · Accepted Answer

They have same number of bonding molecular orbitals and same number of antibonding molecular orbitals

Vedclass · Answer

(B) The correct statement is $(b)$.All these molecules $(C_2, N_2, O_2, F_2)$ are formed by the combination of atomic orbitals of the second period elements.In each case,the total number of atomic orbitals involved is $10$ ($5$ from each atom),which results in the formation of $5$ bonding molecular orbitals $(BMOs)$ and $5$ antibonding molecular orbitals $(ABMOs)$ in the molecular orbital diagram (considering the $1s$ shell).Therefore,they all possess the same number of bonding and antibonding molecular orbitals.

List-$I$	List-$II$
$A. Li_2$	$i. 3$
$B. N_2$	$ii. 1.5$
$C. Be_2$	$iii. 1.0$
$D. O_2$	$iv. 0$
	$v. 2$

Observe the following molecules: $C_2, N_2, O_2, F_2$. Which one of the following statements is correct for the above molecules?

Similar Questions

Explain the formation of $H_{2}$ and the energy level diagram of the $H_{2}$ molecule.

$N_2$ and $O_2$ are converted into $N_2^+$ and $O_2^+$ respectively. Which of the following is not correct?

Select the incorrect statement.

Match the molecules in List-$I$ with their respective bond orders in List-$II$.
List-$I$ List-$II$
$A. Li_2$ $i. 3$
$B. N_2$ $ii. 1.5$
$C. Be_2$ $iii. 1.0$
$D. O_2$ $iv. 0$
$v. 2$

Which among the following have diamagnetic property?
$(i)$ $B_2$
$(ii)$ $N_2$
$(iii)$ $O_2$
$(iv)$ $C_2$

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