(A) Lewis acids are electron-pair acceptors. $AlCl_3$ (incomplete octet),$H^{+}$ (cation),$Co^{3+}$ (cation),$Mg^{2+}$ (cation),and $BF_3$ (incomplete

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(A) Lewis acids are electron-pair acceptors. $AlCl_3$ (incomplete octet),$H^{+}$ (cation),$Co^{3+}$ (cation),$Mg^{2+}$ (cation),and $BF_3$ (incomplete octet) are all Lewis acids. $NH_3$ (lone pair donor),$OH^{-}$ (lone pair donor),and $Cl^{-}$ (lone pair donor) are Lewis bases. Therefore,there are $5$ Lewis acids in the given list.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Acids and Bases

Medium

Observe the following species: $AlCl_3, NH_3, H^{+}, Co^{3+}, OH^{-}, Mg^{2+}, BF_3, Cl^{-}$. How many Lewis acids are present in the above list?

AP EAMCET 2023 All AP EAMCET

A
$5$
B
$4$
C
$2$
D
$3$

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6-2.Equilibrium-II (Ionic Equilibrium)

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Acids and Bases

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Match the following acids in List-$I$ with their respective acid dissociation constants $(K_a)$ in List-$II$:
List-$I$ (Acid) List-$II$ $(K_a)$
$A$. Phenol $I$. $1 \times 10^{-13}$
$B$. Benzoic acid $II$. $3.0 \times 10^{-8}$
$C$. $HClO$ $III$. $1.0 \times 10^{-10}$
$D$. $CH_3COOH$ $IV$. $6.5 \times 10^{-5}$
$V$. $1.75 \times 10^{-5}$

The correct match is:

List-$I$ (Acid)	List-$II$ $(K_a)$
$A$. Phenol	$I$. $1 \times 10^{-13}$
$B$. Benzoic acid	$II$. $3.0 \times 10^{-8}$
$C$. $HClO$	$III$. $1.0 \times 10^{-10}$
$D$. $CH_3COOH$	$IV$. $6.5 \times 10^{-5}$
	$V$. $1.75 \times 10^{-5}$