Observe the following statements:Statement-I: | vedclass

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(C) For ${SF}_6$: The central atom $S$ has $6$ valence electrons and forms $6$ bonds with $F$ atoms. The steric number is $6 + 0 = 6$,which correspond

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Statement $I$ is not correct,but statement $II$ is correct

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(C) For ${SF}_6$: The central atom $S$ has $6$ valence electrons and forms $6$ bonds with $F$ atoms. The steric number is $6 + 0 = 6$,which corresponds to $sp^3d^2$ hybridisation and an octahedral geometry.For ${BrF}_5$: The central atom $Br$ has $7$ valence electrons. It forms $5$ bonds with $F$ atoms and has $1$ lone pair. The steric number is $5 + 1 = 6$,which corresponds to $sp^3d^2$ hybridisation. The geometry is square pyramidal due to the presence of one lone pair.Statement-$I$ says hybridisation is not the same,which is incorrect because both are $sp^3d^2$.Statement-$II$ says ${BrF}_5$ is square pyramidal and ${SF}_6$ is octahedral,which is correct.

Observe the following statements:
Statement-$I$: Hybridisation is not the same in both ${SF}_6$ and ${BrF}_5$.
Statement-$II$: ${BrF}_5$ is square pyramidal while ${SF}_6$ is octahedral in shape.
The correct answer is:

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Observe the following statements:Statement-$I$: Hybridisation is not the same in both ${SF}_6$ and ${BrF}_5$.Statement-$II$: ${BrF}_5$ is square pyramidal while ${SF}_6$ is octahedral in shape.The correct answer is: