Of a normal couple,half the sons are haemophi | vedclass

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(C) Haemophilia is an $X-$linked recessive disorder.Let the normal allele be $X^H$ and the haemophilic allele be $X^h$.If the mother is a carrier $(X^

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One $X-$chromosome of mother

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(C) Haemophilia is an $X-$linked recessive disorder.Let the normal allele be $X^H$ and the haemophilic allele be $X^h$.If the mother is a carrier $(X^H X^h)$ and the father is normal $(X^H Y)$,the cross is as follows:$X^H X^h 	imes X^H Y$Offspring genotypes: $X^H X^H$ (normal daughter),$X^H X^h$ (carrier daughter),$X^H Y$ (normal son),$X^h Y$ (haemophilic son).In this scenario,$50\%$ of the sons are haemophilic and $50\%$ of the daughters are carriers.Therefore,the gene is located on one $X-$chromosome of the mother.

Column-$I$	Column-$II$
$(P)$ Haemophilia	$(i)$ Recessive gene: $X^{h}X^{h}$
$(Q)$ Colour blindness	$(ii)$ Recessive gene: $pp$
$(R)$ Phenylketonuria	$(iii)$ Recessive gene: $Hb^{s}Hb^{s}$
$(S)$ Sickle-cell anaemia	$(iv)$ Recessive gene: $X^{c}X^{c}$

Of a normal couple,half the sons are haemophilic while half the daughters are carriers. The gene is located on $:-$

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