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(D) To determine the electronic configuration,we count the total number of electrons in each species:$1$. For $C$ (Carbon,atomic number $Z=6$),the num

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$C$ and $N^{+}$

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(D) To determine the electronic configuration,we count the total number of electrons in each species:$1$. For $C$ (Carbon,atomic number $Z=6$),the number of electrons is $6$.$2$. For $N^{+}$ (Nitrogen ion,atomic number $Z=7$),the number of electrons is $7 - 1 = 6$.Since both $C$ and $N^{+}$ have $6$ electrons,they are isoelectronic and possess the same electronic configuration $(1s^{2} 2s^{2} 2p^{2})$.Therefore,the correct pair is $C$ and $N^{+}$.

$1$. Burning candle	$i$. Line spectrum
$2$. Sodium vapour	$ii$. Continuous spectrum
$3$. Bunsen flame	$iii$. Band spectrum
$4$. Dark lines in solar spectrum	$iv$. Absorption spectrum

List-$I$	List-$II$
$1$. Nitrogen molecules	$(A)$ Continuous spectrum
$2$. Incandescent solids	$(B)$ Absorption spectrum
$3$. Fraunhofer lines	$(C)$ Band spectrum
$4$. Electric arc between iron rods	$(D)$ Emission spectrum

Of the following pairs of species,which one will have the same electronic configuration for both members?

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