Of the following species,the one having a squ | vedclass

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(C) To determine the geometry,we calculate the hybridization of the central atom:$1$. $NH_4^+$: $N$ has $5$ valence electrons. Steric number = $0.5

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$XeF_4$

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(C) To determine the geometry,we calculate the hybridization of the central atom:$1$. $NH_4^+$: $N$ has $5$ valence electrons. Steric number = $0.5 	imes (5 + 4 - 1) = 4$ ($sp^3$ hybridization,tetrahedral).$2$. $BF_4^-$: $B$ has $3$ valence electrons. Steric number = $0.5 	imes (3 + 4 + 1) = 4$ ($sp^3$ hybridization,tetrahedral).$3$. $XeF_4$: $Xe$ has $8$ valence electrons. Steric number = $0.5 	imes (8 + 4) = 6$ ($sp^3d^2$ hybridization). With $4$ bond pairs and $2$ lone pairs,the geometry is square planar.$4$. $SCl_4$: $S$ has $6$ valence electrons. Steric number = $0.5 	imes (6 + 4) = 5$ ($sp^3d$ hybridization). With $4$ bond pairs and $1$ lone pair,the geometry is see-saw.Thus,$XeF_4$ has a square planar structure.

List-$I$	List-$II$
$A$. $H_3O^+$	$I$. Tetrahedral
$B$. Acetylide anion	$II$. Linear
$C$. $NH_4^+$	$III$. Pyramidal
$D$. $ClO_2^-$	$IV$. Bent

Of the following species,the one having a square planar structure is:

Similar Questions

The tetra-atomic molecules/ions with different shapes are

The geometry with respect to the central atom of the following molecules are: $N(SiH_3)_3;\, Me_3N;\, (SiH_3)_3P$

Match List-$I$ with List-$II$ :

List-$I$ List-$II$

$A$. $H_3O^+$ $I$. Tetrahedral

$B$. Acetylide anion $II$. Linear

$C$. $NH_4^+$ $III$. Pyramidal

$D$. $ClO_2^-$ $IV$. Bent

Choose the correct answer from the options given below :

Which of the following has a tetrahedral shape?

Which of the following molecules has the lowest bond angle?

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