On 0^{circ}C,the pressure measured by a barom | vedclass

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(D) According to the Gay-Lussac's Law for a fixed mass of gas at constant volume,the pressure $P$ is directly proportional to the absolute temperature

Vedclass · Accepted Answer

None of these

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(D) According to the Gay-Lussac's Law for a fixed mass of gas at constant volume,the pressure $P$ is directly proportional to the absolute temperature $T$ $(P \propto T)$.Given:Initial pressure $P_1 = 760 \, mm$ at temperature $T_1 = 0^{\circ}C = 273 \, K$.Final temperature $T_2 = 100^{\circ}C = 373 \, K$.Using the relation $\frac{P_2}{P_1} = \frac{T_2}{T_1}$:$P_2 = P_1 	imes \frac{T_2}{T_1}$$P_2 = 760 	imes \frac{373}{273}$$P_2 \approx 1038 \, mm$.Since $1038 \, mm$ is not among the options,the correct choice is $D$.

On $0^{\circ}C$,the pressure measured by a barometer is $760 \, mm$. What will be the pressure at $100^{\circ}C$?

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