On adding AgNO_3 solution into KI solution,a | vedclass

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Question

(D) The reaction between $AgNO_3$ and $KI$ is: $AgNO_3 + KI \rightarrow AgI(s) + KNO_3$. $A$ negatively charged colloidal sol of $AgI$ is formed when

Vedclass · Accepted Answer

$100 \ mL$ of $0.1 \ M$ $AgNO_3 + 100 \ mL$ of $0.15 \ M$ $KI$

Vedclass · Answer

(D) The reaction between $AgNO_3$ and $KI$ is: $AgNO_3 + KI ightarrow AgI(s) + KNO_3$. $A$ negatively charged colloidal sol of $AgI$ is formed when $KI$ is in excess,as $I^-$ ions are adsorbed on the surface of $AgI$ particles. In option $A$: $100 \ mL 	imes 0.1 \ M = 10 \ mmol$ of $AgNO_3$ and $10 \ mmol$ of $KI$. This results in a neutral sol. In option $B$: $100 \ mL 	imes 0.1 \ M = 10 \ mmol$ of $AgNO_3$ and $50 \ mL 	imes 0.2 \ M = 10 \ mmol$ of $KI$. This results in a neutral sol. In option $C$: $200 \ mL 	imes 0.1 \ M = 20 \ mmol$ of $AgNO_3$ and $200 \ mL 	imes 0.1 \ M = 20 \ mmol$ of $KI$. This results in a neutral sol. In option $D$: $100 \ mL 	imes 0.1 \ M = 10 \ mmol$ of $AgNO_3$ and $100 \ mL 	imes 0.15 \ M = 15 \ mmol$ of $KI$. Here,$KI$ is in excess $(15 \ mmol > 10 \ mmol)$,leading to the adsorption of $I^-$ ions and the formation of a negatively charged sol.

On adding $AgNO_3$ solution into $KI$ solution,a negatively charged colloidal sol is obtained when they are in:

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