(B) The energy released per fission is $E = 200 \text{ MeV} = 200 \times 10^6 \times 1.6 \times 10^{-19} \text{ J} = 3.2 \times 10^{-11} \text{ J}$.Gi

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(B) The energy released per fission is $E = 200 \text{ MeV} = 200 \times 10^6 \times 1.6 \times 10^{-19} \text{ J} = 3.2 \times 10^{-11} \text{ J}$.Given power output $P = 1.6 \text{ MW} = 1.6 \times 10^6 \text{ W}$.The rate of fission $R$ is given by the formula $R = P / E$.Substituting the values: $R = (1.6 \times 10^6) / (3.2 \times 10^{-11})$.$R = 0.5 \times 10^{17} = 5 \times 10^{16} \text{ fissions/s}$.

Class 12 Physics Nuclei Nuclear Fission, Fusion and Nuclear Reactor

Medium

On bombarding $U^{235}$ by slow neutrons,$200 \text{ MeV}$ of energy is released. If the power output of an atomic reactor is $1.6 \text{ MW}$,then the rate of fission will be:

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A
$5 \times 10^{22} / s$
B
$5 \times 10^{16} / s$
C
$8 \times 10^{16} / s$
D
$20 \times 10^{16} / s$

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On bombarding $U^{235}$ by slow neutrons,$200 \text{ MeV}$ of energy is released. If the power output of an atomic reactor is $1.6 \text{ MW}$,then the rate of fission will be:

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