On colliding in a closed container,the gas mo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the Kinetic Theory of Gases,gas molecules are in constant random motion. When these molecules collide with the walls of a closed cont

Vedclass · Accepted Answer

Transfer momentum to the walls

Vedclass · Answer

(A) According to the Kinetic Theory of Gases,gas molecules are in constant random motion. When these molecules collide with the walls of a closed container,they undergo a change in velocity (specifically,a change in the component of velocity perpendicular to the wall). Since momentum is defined as $p = mv$,a change in velocity implies a change in momentum. By Newton's Second Law,the rate of change of momentum is equal to the force exerted. Therefore,the molecules exert a force on the walls by transferring momentum to them,which manifests as gas pressure.

On colliding in a closed container,the gas molecules:

Similar Questions

Assuming the expression for the pressure exerted by the gas,it can be shown that pressure is

The translational kinetic energy of gas molecules for one mole of the gas is equal to

$A$ gas is contained in a vessel at pressure $P_0$. If the mass of all molecules is halved and their speed is doubled,what will be the final pressure?

The pressure of a gas is proportional to

The total kinetic energy of $1 \text{ mole}$ of $N_2$ at $27^{\circ}C$ is approximately: $(R = 2 \text{ cal/mol K})$

Vedclass Test Series

Exam Paper Generator

Online Exam Module