On dividing p(x) = 3x^3 - 6x^2 + 5x - 10 by ( | vedclass

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(D) To find the remainder when $p(x) = 3x^3 - 6x^2 + 5x - 10$ is divided by $(x - 2)$,we use the Remainder Theorem.According to the Remainder Theorem,

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$0$

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(D) To find the remainder when $p(x) = 3x^3 - 6x^2 + 5x - 10$ is divided by $(x - 2)$,we use the Remainder Theorem.According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$a = 2$.Substitute $x = 2$ into the polynomial $p(x)$:$p(2) = 3(2)^3 - 6(2)^2 + 5(2) - 10$$p(2) = 3(8) - 6(4) + 10 - 10$$p(2) = 24 - 24 + 10 - 10$$p(2) = 0$Therefore,the remainder is $0$.

On dividing $p(x) = 3x^3 - 6x^2 + 5x - 10$ by $(x - 2)$,find the remainder.

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