On heating with concentrated NaOH solution in | vedclass

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Question

(B) The reaction of white phosphorus with concentrated $NaOH$ is: $P_{4} + 3NaOH + 3H_{2}O \xrightarrow{\Delta, CO_{2}} 3NaH_{2}PO_{2} + PH_{3}\uparro

Vedclass · Accepted Answer

It is more basic than $NH_{3}$.

Vedclass · Answer

(B) The reaction of white phosphorus with concentrated $NaOH$ is: $P_{4} + 3NaOH + 3H_{2}O \xrightarrow{\Delta, CO_{2}} 3NaH_{2}PO_{2} + PH_{3}\uparrow$ (phosphine). $PH_{3}$ is less basic than $NH_{3}$ because the lone pair of electrons on the phosphorus atom is less available for donation compared to nitrogen,due to the larger size of the phosphorus atom and the involvement of $s$-character in the bonding. Therefore,the statement that $PH_{3}$ is more basic than $NH_{3}$ is incorrect.

On heating with concentrated $NaOH$ solution in an inert atmosphere of $CO_{2}$,white phosphorus gives a gas. Which of the following statements is incorrect about the gas?

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