On passing $C$ ampere of electricity through an electrolyte solution for $t$ seconds,$m$ grams of metal are deposited on the cathode. The equivalent weight $E$ of the metal is:

  • A
    $E = \frac{C \times t}{m \times 96500}$
  • B
    $E = \frac{C \times m}{t \times 96500}$
  • C
    $E = \frac{96500 \times m}{C \times t}$
  • D
    $E = \frac{C \times t \times 96500}{m}$

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