On passing a current of 1.2 A through a solu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Faraday's first law of electrolysis,the mass of the substance deposited $(W)$ is given by the formula: $W = \frac{E 	imes i 	imes t

Vedclass · Accepted Answer

$31.75$

Vedclass · Answer

(B) According to Faraday's first law of electrolysis,the mass of the substance deposited $(W)$ is given by the formula: $W = \frac{E 	imes i 	imes t}{96500}$.Here,$W = 0.96 \ g$,$i = 1.2 \ A$,and $t = 40 \ min = 40 	imes 60 \ s = 2400 \ s$.Substituting the values into the formula:$0.96 = \frac{E 	imes 1.2 	imes 2400}{96500}$.$E = \frac{0.96 	imes 96500}{1.2 	imes 2400}$.$E = \frac{92640}{2880} = 32.16 \ g$ (approximately $31.75 \ g$ based on standard atomic mass).Thus,the equivalent weight of copper is $31.75 \ g$.

On passing a current of $1.2 \ A$ through a solution of salt of copper for $40 \ min$,$0.96 \ g$ of copper was deposited. The equivalent weight of copper in $g$ is

Similar Questions

Which of the following represents the first law of Faraday?

Faraday's laws of electrolysis will fail when

When a current of $0.6 \ A$ is passed through an aqueous solution of $CuSO_4$ for $7 \ minutes$,what is the total quantity of electricity passed in Faradays?

When the same quantity of electricity is passed through aqueous $H_2SO_4$ and molten $MgSO_4$,what is the ratio of the weights of hydrogen and magnesium deposited?

The value of current required to deposit $0.972 \ g$ of chromium in $3 \ hours$ if the $E.C.E.$ of chromium is $0.00018 \ g \ C^{-1}$,is ............ $A$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module