On reduction with hydrogen,$3.6 \ g$ of an oxide of metal $(M)$ left $3.2 \ g$ of the metal. If the atomic weight of the metal is $64$,the formula of the oxide is:

  • A
    $M_2O_3$
  • B
    $M_2O$
  • C
    $MO$
  • D
    $MO_2$

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