On treating a mixture of two alkyl halides wi | vedclass

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(A) The reaction described is the Wurtz reaction,where alkyl halides react with $Na$ metal in dry ether to form alkanes.To obtain $2-$methylpropane $(

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$2-$chloropropane and chloromethane

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(A) The reaction described is the Wurtz reaction,where alkyl halides react with $Na$ metal in dry ether to form alkanes.To obtain $2-$methylpropane $(CH_3-CH(CH_3)-CH_3)$,the alkyl groups involved must be an isopropyl group $(CH_3-CH(CH_3)-)$ and a methyl group $(-CH_3)$.Therefore,the reactants are $2-$chloropropane $(CH_3-CH(Cl)-CH_3)$ and chloromethane $(CH_3Cl)$.The reaction is: $CH_3-CH(Cl)-CH_3 + CH_3Cl + 2Na \xrightarrow{	ext{dry ether}} CH_3-CH(CH_3)-CH_3 + 2NaCl$.

On treating a mixture of two alkyl halides with sodium metal in dry ether,$2-$methylpropane was obtained. The alkyl halides are

Similar Questions

In which of the following reactions does the carbon number not change on product formation?
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$(ii)$ Alkyl halide reduction
$(iii)$ Wurtz reaction
$(iv)$ Decarboxylation
$(v)$ Kolbe reaction

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Name the reaction:
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The above reaction is called:

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