On treatment of $100 \ mL$ of $0.1 \ M$ solution of $CoCl_3 \cdot 6H_2O$ with excess $AgNO_3$,$1.2 \times 10^{22}$ ions are precipitated. The complex is:

  • A
    $[Co(H_2O)_4 Cl_2]Cl \cdot 2H_2O$
  • B
    $[Co(H_2O)_3 Cl_3] \cdot 3H_2O$
  • C
    $[Co(H_2O)_6]Cl_3$
  • D
    $[Co(H_2O)_5 Cl]Cl_2 \cdot H_2O$

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