One $year$ ago,a father was four times as old as his son. In $6$ $years$ time,his age will exceed twice his son's age by $9$ $years$. The ratio of their present ages is:

In a family,mother's age is twice that of daughter's age. Father is $10 \,years$ older than mother. Brother is $20 \,years$ younger than his mother and $5 \,years$ older than his sister. What is the age of the father? (in $years$)

Jayesh is as much younger to Anil as he is older to Prashant. If the sum of the ages of Anil and Prashant is $48 \text{ years}$,what is the age of Jayesh? (in $years$)

$7$ years ago,the ages (in years) of $A$ and $B$ were in the ratio $4:5$; and $7$ years hence they will be in the ratio $5:6$. The present age of $B$ is (in years):

The average age of women and child workers in a factory was $15 \text{ years}$. The average age of all the $16$ children was $8 \text{ years}$ and the average age of women workers was $22 \text{ years}$. If $10$ women workers were married,then the number of unmarried women workers is:

The ages of $A$ and $B$ are in the ratio $6: 5$ and the sum of their ages is $44 \text{ years}$. The ratio of their ages after $8 \text{ years}$ will be: