(B) By definition, $1 \text{ } \mathring{A} = 10^{-10} \text{ m}$. To convert this into millimeters $(\text{mm})$, we know that $1 \text{ m} = 10^3 \t

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(B) By definition, $1 \text{ } \mathring{A} = 10^{-10} \text{ m}$. To convert this into millimeters $(\text{mm})$, we know that $1 \text{ m} = 10^3 \text{ mm}$. Therefore, $1 \text{ } \mathring{A} = 10^{-10} \times 10^3 \text{ mm}$. $1 \text{ } \mathring{A} = 10^{-7} \text{ mm}$. Thus, the correct option is $B$.

Class 11 Physics Units, Dimensions and Measurement Units

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One $\mathring{A}$ is equal to:

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A
$10^{-6} \text{ mm}$
B
$10^{-7} \text{ mm}$
C
$10^{-8} \text{ mm}$
D
$10^{-9} \text{ mm}$

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Units, Dimensions and Measurement

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Units

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How many light-years are in $1$ parsec? And how many astronomical units are in $1$ light-year?

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The $SI$ unit of length is 'metre'. Suppose we adopt a new unit of length which equals $x$ metre. Then,the area of $1 \ m^2$ expressed in terms of the new unit has a magnitude of:

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Lux is a unit of

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Match List-$I$ with List-$II$ and select the correct answer by using the codes given below the lists.

List-$I$ List-$II$

$(A)$ Distance between earth and stars $(1)$ Microns

$(B)$ Inter-atomic distance in a solid $(2)$ $\mathring{A}$s

$(C)$ Size of the nucleus $(3)$ Light years

$(D)$ Wavelength of infrared laser $(4)$ Fermi

List-$I$	List-$II$
$(A)$ Distance between earth and stars	$(1)$ Microns
$(B)$ Inter-atomic distance in a solid	$(2)$ $\mathring{A}$s
$(C)$ Size of the nucleus	$(3)$ Light years
$(D)$ Wavelength of infrared laser	$(4)$ Fermi