One card is drawn randomly from a pack of 52 | vedclass

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(C) Let $A$ be the event of drawing a king and $B$ be the event of drawing a spade.Total number of cards $= 52$.Number of kings $n(A) = 4$,so $P(A) =

Vedclass · Accepted Answer

$\frac{4}{13}$

Vedclass · Answer

(C) Let $A$ be the event of drawing a king and $B$ be the event of drawing a spade.Total number of cards $= 52$.Number of kings $n(A) = 4$,so $P(A) = \frac{4}{52} = \frac{1}{13}$.Number of spades $n(B) = 13$,so $P(B) = \frac{13}{52} = \frac{1}{4}$.The card that is both a king and a spade is the king of spades,so $n(A \cap B) = 1$,and $P(A \cap B) = \frac{1}{52}$.Using the addition theorem of probability,$P(A \cup B) = P(A) + P(B) - P(A \cap B)$.$P(A \cup B) = \frac{4}{52} + \frac{13}{52} - \frac{1}{52} = \frac{16}{52} = \frac{4}{13}$.

One card is drawn randomly from a pack of $52$ cards. The probability that it is a king or a spade is:

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