One end of the diameter of the circle $x^2+y^2-6x-5y-1=0$ is $(-1,3)$. Find the equation of the tangent at the other end of the diameter.

  • A
    $8x+y-58=0$
  • B
    $8x-2y-52=0$
  • C
    $8x-y-54=0$
  • D
    $8x+2y-60=0$

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