One gas bleaches the colour of flowers by red | vedclass

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(D) The aqueous solution of $SO_2$ acts as a reducing agent.$SO_2 + 2H_2O 	o H_2SO_4 + 2[H]$Thus,$SO_2$ in the presence of moisture is used as a blea

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$SO_2$ and $Cl_2$

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(D) The aqueous solution of $SO_2$ acts as a reducing agent.$SO_2 + 2H_2O 	o H_2SO_4 + 2[H]$Thus,$SO_2$ in the presence of moisture is used as a bleaching agent due to its reducing nature.$	ext{Coloured matter} + [H] \longrightarrow 	ext{Colourless matter}$Similarly,$Cl_2$ acts as a bleaching agent in the presence of moisture due to its oxidizing nature:$Cl_2 + H_2O 	o 2HCl + [O]$$	ext{Coloured matter} + [O] \longrightarrow 	ext{Colourless matter}$Therefore,the correct pair is $SO_2$ and $Cl_2$.

One gas bleaches the colour of flowers by reduction,while the other by oxidation,the two gases respectively are

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