One mole of an organic compound (A) with the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The molecular formula $C_3H_8O$ corresponds to either an alcohol or an ether. Since it reacts with $HI$ to form two products ($X$ and $Y$),it must

Vedclass · Accepted Answer

Methoxy ethane

Vedclass · Answer

(D) The molecular formula $C_3H_8O$ corresponds to either an alcohol or an ether. Since it reacts with $HI$ to form two products ($X$ and $Y$),it must be an ether. The reaction is: $CH_3-CH_2-O-CH_3 + 2HI \rightarrow CH_3-I (X) + CH_3-CH_2-I (Y) + H_2O$.When ethyl iodide $(Y)$ is boiled with aqueous alkali $(NaOH)$,it forms ethanol $(CH_3CH_2OH)$.However,the iodoform test is given by compounds containing the $CH_3CO-$ group or $CH_3CH(OH)-$ group. Ethanol $(CH_3CH_2OH)$ gives a positive iodoform test. Thus,$(A)$ is methoxyethane.

One mole of an organic compound $(A)$ with the formula $C_3H_8O$ reacts completely with two moles of $HI$ to form $X$ and $Y$. When $Y$ is boiled with aqueous alkali it forms $Z$. $Z$ answers the iodoform test. The compound $(A)$ is

Similar Questions

Which of the following aromatic ethers does not undergo cleavage by $HI$ at $525 \ K$?

The following are possible syntheses of phenyl propyl ether. Which one would work?
$(i)$ $C_6H_5OH$ $\xrightarrow{KNH_2}$ $\xrightarrow{CH_3CH_2CH_2Br}$
(ii) $CH_3CH_2CH_2OH$ $\xrightarrow{NaOH}$ $\xrightarrow{C_6H_5Br}$
(iii) $CH_3CH_2CH_2OH$ $\xrightarrow{NaH}$ $\xrightarrow{C_6H_5Br}$

The $C - O - C$ bond angle in ethers is approximately -

The bond angle of $C-O-C$ bond in methoxy methane is (in $^{\circ}$)

In which of the following reactions is the product an ether?

Vedclass Test Series

Exam Paper Generator

Online Exam Module