One mole of fluorine is reacted with two moles of hot concentrated $KOH$. The products formed are $KF, H_2O$ and $O_2$. The molar ratio of $KF, H_2O$ and $O_2$,respectively is
- A$2 : 1 : 0.5$
- B$4 : 2 : 1$
- C$1 : 2 : 1$
- D$2 : 1 : 2$
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