One of the solutions of the quadratic equatio | vedclass

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(C) Given the quadratic equation: $(x-3)^{2}-4=0$We can rewrite this as: $(x-3)^{2}=4$Taking the square root on both sides,we get: $x-3 = \pm \sqrt{4}

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$1$

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(C) Given the quadratic equation: $(x-3)^{2}-4=0$We can rewrite this as: $(x-3)^{2}=4$Taking the square root on both sides,we get: $x-3 = \pm \sqrt{4}$$x-3 = \pm 2$This gives two possible cases:Case $1$: $x-3 = 2 \implies x = 2+3 = 5$Case $2$: $x-3 = -2 \implies x = -2+3 = 1$The solutions are $x=5$ and $x=1$.Comparing this with the given options,$1$ is one of the solutions.

One of the solutions of the quadratic equation $(x-3)^{2}-4=0$ is ..... .

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