One of the zeroes of the polynomial 2x^2 + 7x | vedclass

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Question

(C) Let the polynomial be $p(x) = 2x^2 + 7x - 4$.To find the zeroes,we set $p(x) = 0$:$2x^2 + 7x - 4 = 0$$2x^2 + 8x - x - 4 = 0$$2x(x + 4) - 1(x + 4)

Vedclass · Accepted Answer

$\frac{1}{2}$

Vedclass · Answer

(C) Let the polynomial be $p(x) = 2x^2 + 7x - 4$.To find the zeroes,we set $p(x) = 0$:$2x^2 + 7x - 4 = 0$$2x^2 + 8x - x - 4 = 0$$2x(x + 4) - 1(x + 4) = 0$$(2x - 1)(x + 4) = 0$This gives $2x - 1 = 0$ or $x + 4 = 0$.So,$x = \frac{1}{2}$ or $x = -4$.Comparing these with the given options,$\frac{1}{2}$ is one of the zeroes.Therefore,option $(c)$ is correct.

One of the zeroes of the polynomial $2x^2 + 7x - 4$ is

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