One strand of the given segment of DNA codes | vedclass

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(D) During transcription,the $mRNA$ strand is synthesized complementary to the template strand of $DNA$.In $DNA$,$Adenine$ $(A)$ pairs with $Thymine$

Vedclass · Accepted Answer

$TAG, CGC, AGT$

Vedclass · Answer

(D) During transcription,the $mRNA$ strand is synthesized complementary to the template strand of $DNA$.In $DNA$,$Adenine$ $(A)$ pairs with $Thymine$ $(T)$,and $Guanine$ $(G)$ pairs with $Cytosine$ $(C)$.However,in $mRNA$,$Uracil$ $(U)$ replaces $Thymine$ $(T)$.Given $mRNA$ sequence: $AUC, GCG, UCA$.The template $DNA$ strand must have the complementary bases: $A$ pairs with $T$,$U$ pairs with $A$,$C$ pairs with $G$,$G$ pairs with $C$.Matching the sequence $AUC, GCG, UCA$ to the template $DNA$ strand:$A \rightarrow T$$U \rightarrow A$$C \rightarrow G$$G \rightarrow C$$C \rightarrow G$$G \rightarrow C$$U \rightarrow A$$C \rightarrow G$$A \rightarrow T$Thus,the template strand sequence is $TAG, CGC, AGT$. Therefore,option $D$ is correct.

One strand of the given segment of $DNA$ codes for $mRNA$ having the sequence $AUC, GCG, UCA$ needed for synthesis of proteins. The strand by which $DNA$ molecule will be responsible for the above $mRNA$ sequence is

Similar Questions

Describe the process of transcription in prokaryotes (bacteria).

Assertion: The transcription and translation can be coupled in bacteria.
Reason: In bacteria,since the $\text{mRNA}$ does not require any processing to become active,and also since transcription and translation take place in the same compartment.

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