Out of H_2O and H_2S,which one has a higher b | vedclass

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(A) In $H_2O$ and $H_2S$,the central atoms $O$ and $S$ are $sp^3$ hybridized. Moving down the group,the atomic size of the central atom increases and

Vedclass · Accepted Answer

$H_2O$ due to higher electronegativity of $O$.

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(A) In $H_2O$ and $H_2S$,the central atoms $O$ and $S$ are $sp^3$ hybridized. Moving down the group,the atomic size of the central atom increases and its electronegativity decreases. As the electronegativity of the central atom decreases,the bond pair electrons move further away from the central atom. This results in a decrease in the bond pair-bond pair repulsion,leading to a smaller bond angle in $H_2S$ $(92^\circ)$ compared to $H_2O$ $(104.5^\circ)$. Therefore,$H_2O$ has a higher bond angle.

Out of $H_2O$ and $H_2S$,which one has a higher bond angle and why?

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