Out of hydrogen and air,which will have a hig | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The root mean square speed of a gas molecule is given by the formula $v_{	ext{rms}} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas consta

Vedclass · Accepted Answer

Hydrogen

Vedclass · Answer

(A) The root mean square speed of a gas molecule is given by the formula $v_{	ext{rms}} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas constant,$T$ is the absolute temperature,and $M$ is the molar mass of the gas.Since $v_{	ext{rms}} \propto \frac{1}{\sqrt{M}}$,the gas with the lower molar mass will have a higher $v_{	ext{rms}}$ at the same temperature.The molar mass of hydrogen $(H_2)$ is approximately $2 	ext{ g/mol}$,while the average molar mass of air is approximately $28.97 	ext{ g/mol}$.Since the molar mass of hydrogen is significantly lower than that of air,hydrogen will have a higher $v_{	ext{rms}}$.

Out of hydrogen and air,which will have a higher root mean square speed $(v_{\text{rms}})$?

Similar Questions

In a closed container,the same number of hydrogen $(H_2)$ and carbon dioxide $(CO_2)$ molecules are kept. If a small hole is made in the container,which gas will effuse out faster?

For a particular ideal gas,which of the following graphs represents the variation of the mean squared velocity of the gas molecules with temperature?

The $rms$ speed of a molecule of a diatomic gas is $v$. When the temperature is doubled,the molecule dissociates into two atoms. The new $rms$ speed of the atom is:

In Maxwell's speed distribution curve,for $N_2$ gas,the average relative velocity (in $m/s$) between two molecules at $300 \, K$ is:

For which gas is the $rms$ velocity maximum?

Vedclass Test Series

Exam Paper Generator

Online Exam Module