Out of the following outer electronic configu | vedclass

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(B) The highest oxidation state is achieved by $(n-1) d^5 n s^2$, which corresponds to a maximum oxidation state of $+7$. This is because the $(n-1) d

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$(n-1) d^5 n s^2$

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(B) The highest oxidation state is achieved by $(n-1) d^5 n s^2$, which corresponds to a maximum oxidation state of $+7$. This is because the $(n-1) d$-electrons can participate in bonding along with $n s$-electrons, as their energy levels are comparable. The oxidation states for the given configurations are summarized below:| Electronic configuration | Oxidation state || :--- | :--- || $(n-1) d^8 n s^2$ | $+2, +3, +4$ || $(n-1) d^3 n s^2$ | $+2, +3, +4, +5$ || $(n-1) d^5 n s^1$ | $+2, +3, +4, +5, +6$ || $(n-1) d^5 n s^2$ | $+2, +3, +4, +5, +6, +7$ |

Out of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one?

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