Out of the two compounds shown below,the vapo | vedclass

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(A) Compound $(A)$ is $p$-nitrophenol,which exhibits intermolecular hydrogen bonding,leading to association of molecules and higher boiling point.Comp

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higher than that of $A$

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(A) Compound $(A)$ is $p$-nitrophenol,which exhibits intermolecular hydrogen bonding,leading to association of molecules and higher boiling point.Compound $(B)$ is $o$-nitrophenol,which exhibits intramolecular hydrogen bonding,preventing association of molecules and resulting in a lower boiling point.Since vapour pressure is inversely proportional to the boiling point,compound $(B)$ will have a higher vapour pressure than compound $(A)$.

Out of the two compounds shown below,the vapour pressure of $B$ at a particular temperature is expected to be:

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