Oxidation number of N in ammonium nitrate is | vedclass

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(C) Ammonium nitrate is $NH_4NO_3$,which dissociates into $NH_4^+$ and $NO_3^-$.For $NH_4^+$: Let the oxidation state of $N$ be $x$. Since the oxidati

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$-3$ and $+5$

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(C) Ammonium nitrate is $NH_4NO_3$,which dissociates into $NH_4^+$ and $NO_3^-$.For $NH_4^+$: Let the oxidation state of $N$ be $x$. Since the oxidation state of $H$ is $+1$,we have $x + 4(+1) = +1$,which gives $x = -3$.For $NO_3^-$: Let the oxidation state of $N$ be $y$. Since the oxidation state of $O$ is $-2$,we have $y + 3(-2) = -1$,which gives $y - 6 = -1$,so $y = +5$.Therefore,the oxidation states of $N$ in $NH_4NO_3$ are $-3$ and $+5$.

Oxidation number of $N$ in ammonium nitrate is

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