Oxidation number of Mn in K_2MnO_4 and MnSO_4 | vedclass

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Question

(B) For $K_2MnO_4$: Let the oxidation number of $Mn$ be $x$. The sum of oxidation states is $2(+1) + x + 4(-2) = 0$. Solving gives $2 + x - 8 = 0$,so

Vedclass · Accepted Answer

$+6, +2$

Vedclass · Answer

(B) For $K_2MnO_4$: Let the oxidation number of $Mn$ be $x$. The sum of oxidation states is $2(+1) + x + 4(-2) = 0$. Solving gives $2 + x - 8 = 0$,so $x = +6$.For $MnSO_4$: Let the oxidation number of $Mn$ be $x$. The sulfate ion $SO_4^{2-}$ has an oxidation state of $-2$. Thus,$x + (-2) = 0$,so $x = +2$.Therefore,the oxidation numbers are $+6$ and $+2$ respectively.

Oxidation number of $Mn$ in $K_2MnO_4$ and $MnSO_4$ are respectively

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