The oxidation number of oxygen in an $O_2$ molecule is:

  • A
    $+1$
  • B
    $0$
  • C
    $+2$
  • D
    $-2$

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The oxidation number of $C$ atom in $CH_{2}Cl_{2}$ and $CCl_{4}$ are respectively:

One mole of $N_2H_4$ loses $10 \ moles$ of electrons to form a new compound $Z$. Assuming that all the nitrogen atoms appear in the new compound, what is the oxidation state of nitrogen in $Z$? (There is no change in the oxidation state of hydrogen.)

The oxidation number of $C$ in $CO_2$ is

Explain the Stock notation theory with examples.

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