Oxidation numbers of P in PO_4^{3-},S in SO_4 | vedclass

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(B) For $PO_4^{3-}$: Let the oxidation number of $P$ be $x$. $x + 4(-2) = -3 \implies x - 8 = -3 \implies x = +5$. For $SO_4^{2-}$: Let the oxidation

Vedclass · Accepted Answer

$+5, +6$ and $+6$

Vedclass · Answer

(B) For $PO_4^{3-}$: Let the oxidation number of $P$ be $x$. $x + 4(-2) = -3 \implies x - 8 = -3 \implies x = +5$. For $SO_4^{2-}$: Let the oxidation number of $S$ be $y$. $y + 4(-2) = -2 \implies y - 8 = -2 \implies y = +6$. For $Cr_2O_7^{2-}$: Let the oxidation number of $Cr$ be $z$. $2z + 7(-2) = -2 \implies 2z - 14 = -2 \implies 2z = +12 \implies z = +6$. Thus,the oxidation numbers are $+5, +6$ and $+6$ respectively.

Oxidation numbers of $P$ in $PO_4^{3-}$,$S$ in $SO_4^{2-}$ and that of $Cr$ in $Cr_2O_7^{2-}$ are respectively

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