The oxidation states of S in peroxodisulphuri | vedclass

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Question

(A) In peroxodisulphuric acid $(H_{2}S_{2}O_{8})$,the structure contains a peroxide linkage $(-O-O-)$. The oxidation state of both sulfur atoms is $+6

Vedclass · Accepted Answer

$+6, +5, 0$

Vedclass · Answer

(A) In peroxodisulphuric acid $(H_{2}S_{2}O_{8})$,the structure contains a peroxide linkage $(-O-O-)$. The oxidation state of both sulfur atoms is $+6$.In sodium tetrathionate $(Na_{2}S_{4}O_{6})$,the structure is $O_{3}S-S-S-SO_{3}^{2-}$. The two terminal sulfur atoms are in the $+5$ oxidation state,while the two central sulfur atoms are in the $0$ oxidation state.Therefore,the oxidation states are $+6$ for $H_{2}S_{2}O_{8}$ and $+5, 0$ for $Na_{2}S_{4}O_{6}$.

The oxidation states of $S$ in peroxodisulphuric acid $(H_{2}S_{2}O_{8})$ and sodium tetrathionate $(Na_{2}S_{4}O_{6})$ are respectively:

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