The oxidation state of elemental carbon is:

What are the oxidation numbers of $S$ atoms in $S_4O_6^{2-}$?

If an $M^{3+}$ ion loses $3e^-$,what will be its final oxidation number?

Match the Column-$I$ with Column-$II$ for the oxidation states of the central atoms.

Column-$I$	Column-$II$
$A$. $Cr_2O_7^{2-}$	$1$. $+3$
$B$. $MnO_4^{-}$	$2$. $+4$
$C$. $VO_3^{-}$	$3$. $+5$
$D$. $FeF_6^{3-}$	$4$. $+6$
	$5$. $+7$

$A$ compound contains $x$,$y$,and $z$ atoms. The oxidation number of $x$ is $+3$,$y$ is $-5$,and $z$ is $+1$. The possible formula of the compound is:

What are the oxidation states of the most electronegative element in the products of the reaction between $BaO_2$ and $H_2SO_4$?