The oxidation state of nitrogen is incorrectl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1. [Co(NH_3)_5Cl]Cl_2$: In $NH_3$,the oxidation state of $N$ is $-3$. The given value $0$ is for the neutral molecule $NH_3$,not for $N$ itself.

Vedclass · Accepted Answer

$(N_2H_5)_2SO_4 	o +2$

Vedclass · Answer

(C) $1. [Co(NH_3)_5Cl]Cl_2$: In $NH_3$,the oxidation state of $N$ is $-3$. The given value $0$ is for the neutral molecule $NH_3$,not for $N$ itself. However,checking other options for the most incorrect value.$2. NH_2OH$: $x + 3(+1) - 2 = 0 \implies x = -1$. This is correct.$3. (N_2H_5)_2SO_4$: $2(2x + 5) - 2 = 0 \implies 4x + 10 - 2 = 0 \implies 4x = -8 \implies x = -2$. The given value $+2$ is incorrect.$4. Mg_3N_2$: $3(+2) + 2x = 0 \implies 6 + 2x = 0 \implies x = -3$. This is correct.Thus,option $C$ is the incorrectly stated one.

Compound	Oxidation number
$1$. $C_6H_{12}O_6$ (Carbon)	$a$. $+1$
$2$. $CCl_4$ (Carbon)	$b$. $0$
$3$. $NH_4Cl$ (Nitrogen)	$c$. $+4$
$4$. $Ba(H_2PO_2)_2$ (Phosphorus)	$d$. $-3$

The oxidation state of nitrogen is incorrectly given for:
Compound $\to$ Oxidation state

Similar Questions

The oxidation number of sulphur in $S_8$ molecule is

The difference in the oxidation numbers of the two types of sulphur atoms in $Na_2S_4O_6$ is

The oxidation number of $Cr$ in $K_2Cr_2O_7$ is

Match the following compounds with the oxidation number of the central atom (or specific atom in question):

Compound Oxidation number

$1$. $C_6H_{12}O_6$ (Carbon) $a$. $+1$

$2$. $CCl_4$ (Carbon) $b$. $0$

$3$. $NH_4Cl$ (Nitrogen) $c$. $+4$

$4$. $Ba(H_2PO_2)_2$ (Phosphorus) $d$. $-3$

The oxidation number of $Mn$ in $MnO_4^{-}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The oxidation state of nitrogen is incorrectly given for:Compound $\to$ Oxidation state