The pair of equations 2x + 6y = 10 and 3x + 9 | vedclass

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Question

(B) Given equations are $2x + 6y = 10$ and $3x + 9y - 15 = 0$.Divide the first equation by $2$: $x + 3y = 5$.Divide the second equation by $3$: $x + 3

Vedclass · Accepted Answer

infinitely many solutions

Vedclass · Answer

(B) Given equations are $2x + 6y = 10$ and $3x + 9y - 15 = 0$.Divide the first equation by $2$: $x + 3y = 5$.Divide the second equation by $3$: $x + 3y - 5 = 0$,which implies $x + 3y = 5$.Since both equations represent the same line,the ratio of coefficients is $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} = \frac{1}{1} = \frac{3}{3} = \frac{5}{5}$.Therefore,the pair of equations has infinitely many solutions.

The pair of equations $2x + 6y = 10$ and $3x + 9y - 15 = 0$ has..........

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