Pentaaquachloridochromium (III) chloride mono | vedclass

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Question

(B) The name of the complex is Pentaaquachloridochromium $(III)$ chloride monohydrate.$1$. The central metal atom is Chromium $(Cr)$ with an oxidation

Vedclass · Accepted Answer

$[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$

Vedclass · Answer

(B) The name of the complex is Pentaaquachloridochromium $(III)$ chloride monohydrate.$1$. The central metal atom is Chromium $(Cr)$ with an oxidation state of $+3$.$2$. The ligands are five water molecules $(pentaaqua = 5 \ H_2O)$ and one chloride ion $(chlorido = 1 \ Cl^-)$ inside the coordination sphere.$3$. The counter ion is chloride $(Cl^-)$ outside the coordination sphere.$4$. There is one water molecule of hydration $(monohydrate = 1 \ H_2O)$.$5$. Balancing the charges: $[Cr(H_2O)_5Cl]^{x} + Cl^- = 0$. Since $Cr$ is $+3$ and $Cl$ is $-1$,the complex ion charge is $+2$. Thus,two chloride ions are needed to balance the charge: $[Cr(H_2O)_5Cl]Cl_2$.$6$. Adding the monohydrate: $[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$.

Pentaaquachloridochromium $(III)$ chloride monohydrate complex has the formula.

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