(A) We know that $\sin^2 x = \frac{1 - \cos(2x)}{2}$.The period of $\cos(kx)$ is given by $\frac{2\pi}{|k|}$.Here,$k = 2$,so the period is $\frac{2\pi

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(A) We know that $\sin^2 x = \frac{1 - \cos(2x)}{2}$.The period of $\cos(kx)$ is given by $\frac{2\pi}{|k|}$.Here,$k = 2$,so the period is $\frac{2\pi}{2} = \pi$.Thus,the period of $\sin^2 x$ is $\pi$.

Class 11 Mathematics Trigonometrical Equations Periodic functions

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The period of $\sin^2 x$ is

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A
$\pi$
B
$2\pi$
C
$\frac{\pi}{2}$
D
None of these

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